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Three of the four vertices of a rectangle are (5,11), (6,11)  and (16,-2). What is the area of the intersection of this rectangular region and the region inside the graph of the equation (x - 5)^2 + (y + 2)^2 = 16? Express your answer as a common fraction in terms of pi.

 Dec 23, 2020
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This cannot be a rectangle....see the graph :

 

 

 

 

For this to be a rectangle, angle ABC would have to be  = 90°

 

 

cool cool cool

 Dec 23, 2020

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