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Three over the square root of 7 minus the square root of two

 

                        3

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square root of 7- square root of 2

 

simplify 

Guest Apr 2, 2017
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 #1
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3 / [ sqrt (7) - sqrt (2) ]          

 

Multiply top/bottom by the conjugate  of  [ sqrt (7) - sqrt (2) ] →  [ sqrt (7) + sqrt (2) ]

 

3  [ sqrt (7) + sqrt (2) ] / (  [ sqrt (7) - sqrt (2) ]  [ sqrt (7) + sqrt (2) ]   )   =

 

3  [ sqrt (7) + sqrt (2) ] / ( 7  -  2 )   =

 

3  [ sqrt (7) + sqrt (2) ]  / 5  =

 

(3/5)sqrt (7)   +  (3/5)sqrt (2)

 

 

cool cool cool

CPhill  Apr 2, 2017
edited by CPhill  Apr 2, 2017

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