Three over the square root of 7 minus the square root of two
3
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square root of 7- square root of 2
simplify
+129847 3 / [ sqrt (7) - sqrt (2) ]
Multiply top/bottom by the conjugate of [ sqrt (7) - sqrt (2) ] → [ sqrt (7) + sqrt (2) ]
3 [ sqrt (7) + sqrt (2) ] / ( [ sqrt (7) - sqrt (2) ] [ sqrt (7) + sqrt (2) ] ) =
3 [ sqrt (7) + sqrt (2) ] / ( 7 - 2 ) =
3 [ sqrt (7) + sqrt (2) ] / 5 =
(3/5)sqrt (7) + (3/5)sqrt (2)
