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tickets at the dance that were bought before the were $2 each.Tickets at the door were $3.Altogether 478 tickets were sold and total of 1110 dollars were made.how many tickets were bought before the dance and bought at the door?

 Apr 22, 2015

Best Answer 

 #1
avatar+33654 
+5

Let b = number of tickets bought before and d = number bought at the door.  Then

 

b + d = 478                      (1)

2b + 3d = 1110                (2)

 

Double all terms in (1)

2b + 2d = 956                   (3)

 

Subtract (3) from (2) term by term:

3d - 2d = 1110 - 956

d =  154

 

Put this back into (1):

b + 154 = 478

 

Subtract 154 from both sides:

b = 324

 

So there were 324 tickets bought before and 154 at the door.

.

 Apr 22, 2015
 #1
avatar+33654 
+5
Best Answer

Let b = number of tickets bought before and d = number bought at the door.  Then

 

b + d = 478                      (1)

2b + 3d = 1110                (2)

 

Double all terms in (1)

2b + 2d = 956                   (3)

 

Subtract (3) from (2) term by term:

3d - 2d = 1110 - 956

d =  154

 

Put this back into (1):

b + 154 = 478

 

Subtract 154 from both sides:

b = 324

 

So there were 324 tickets bought before and 154 at the door.

.

Alan Apr 22, 2015

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