This is an interesting problem......
Let R be the radius of the larger circle and r the radius of the smaller circle
Note that F = (0, R) and H = (R,0)
FH = sqrt ( R^2 + R^2 ) = R*sqrt (2)
Likewise BC = r*sqrt (2)
Midpoint of FH = (R/2 R/2)
Distance from O to the midpoint = R/sqrt (2)
Midpoint of BC = (r/2, r,2)
Distance from O to this midpoint = r/sqrt (2)
The quadrilateral is a trapezoid with height = (R + r) / sqrt (2)
And the sum of its bases = sqrt (2) (R + r)
Area of quadrilateral = (1/2) (R + r) / sqrt (2) * ( sqrt (2) (R + r) ) = (1/2) ( R + r)^2
Area between the circles = pi (R^2 - r^2)
Area of quadrilateral / area between circles = 2/3
So
(1/2) (R + r)^2 2
___________ = ____
pi (R^2 - r^2) 3
(1/2) (R + r) (R + r) 2
_______________ = ___
pi ( R + r) ( R - r) 3
(1/2) (R + r) 2
_________ = ________ cross-multiply
pi (R - r) 3
(3/2) ( R + r) = 2pi ( R - r)
(3/2)R + (3/2)r = 2pi R - 2pi r
( 2pi + 3/2 ) r = (2pi - 3/2) R
r / R = (2pi - 3/2) / ( 2pi + 3/2 ) ≈ .6145
Large circle radius R = ? Small circle radius r = 1
Large circle area Al = R2pi Small circle area As = pi
Trapezoid area At = R2/2 + R + 1/2
Annular ring area Ar = R2pi - pi
R2pi - pi / (R2/2 + R + 1/2) = 3/2
R = 1.62719711 units
So, the ratio is 1 : 1.62719711 or 0.614553697