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I have the sum of X+Y

is it possible to get the correct numbers off of this? or is it too Large to determine?

X+Y=71405944055637250040191947337910352151049351313163998814316054262056455582087

is there a site online that could assist me.

Guest Aug 6, 2017

#1**0 **

Well, you could divide your number by any smaller number such as 2 and adjust the last digits to add up to your original number. So dividing by 2 will give you these 2 numbers. The number is not EVEN, so you get a fraction at the end because you are dividing 7 by 2 =3.5. Then adjust the last 2 digits to 3 and 4 and then add the 2 numbers together to get your original number. Like this:

35702972027818625020095973668955176075524075656581999407158027131028227791043 + 35702972027818625020095973668955176075524075656581999407158027131028227791044=

71405944055637250040191947337910352151049351313163998814316054262056455582087.

You could do that by dividing it by any number from 2 and up. You could also subtract any number you want from your original number and have two numbers that will add up to your original number. However, it is much more difficult to factor such large number into its prime factors. This one turns out to be relatively easy to factor. This is much more important in math than just finding two numbers that will add up to the original number:

7140594 4055637250 0401919473 3791035215 1049351313 1639988143 1605426205 6455582087 (77 digits) = 11 × 1092 × 972119 × 172 9725211873 × 3249 3174077067 1429652325 3645629856 3167127445 2972086011 (54 digits).

Have fun with numbers!!.

Guest Aug 6, 2017

#2**0 **

Ok, so im trying to grasp the math on factoring such a large number

Can you help me out? Making an even number i think

49178638447116951866515857205742587579865087301583229603671018102900695896488

so i break it down to here

24589319223558475933257928602871293789932543650791614801835509051450347948244

24589319223558475933257928602871293789932543650791614801835509051450347948244

thank you

Guest Aug 6, 2017

#3**0 **

It is very difficult with very big numbers. Of course, as long as it is EVEN, you can always divide by 2 until you get an ODD number. After that, it becomes much more difficult. Only very advanced and complicated algorithms can factor such large numbers. Even then, if the number becomes too large, such as 500-digit number, even the fastest supercomputers cannot factor it. And that is how the internet uses huge numbers to encrypt information about online purchases and online banking...etc.

I have such an algorithm on my computer which can crack relatively large numbers, such as this one you came up with:

4917863 8447116951 8665158572 0574258757 9865087301 5832296036 7101810290 0695896488 (77 digits) = 2^3 × 7 × 94 3365688047 3820919255 6236008691 (32 digits) × 930 9115048350 5505083439 9070994494 3748867153 (43 digits)

Guest Aug 6, 2017

#4**0 **

So how well would your algorithm be at breaking down this number? just curios, for some encrytion im trying

404126452721671984105120106983499734291514771721480455653591241555357135141949795080744945211593806816161832469023796413516878337559089400655080442734197 (153)

Guest Aug 7, 2017

#5**0 **

404 1264527216 7198410512 0106983499 7342915147 7172148045 5653591241 5553571351 4194979508 0744945211 5938068161 6183246902 3796413516 8783375590 8940065508 0442734197 (153 digits) = 11 × 109^2 × 972119 × 45 8794766603 × 172 9725211873 × 1262 5403074419 6009147841 × 31747 6324118287 6692543363 8881510887 3639133034 5815181089 6280330376 5669567233 0437942957 0985533267 (95 digits)

As you can see, it can factor a good portion of it, but it is STUCK in the last 95 digits!!. This last 95-digit number is not prime but composite, but it cannot handle it so far. It may take it days or weeks to factor it!.

Guest Aug 7, 2017

edited by
Guest
Aug 7, 2017