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I'm stuck on this problem. I would appreciate help!

 May 29, 2016

Best Answer 

 #3
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+20

Each element of S is a product of 5 consequtive numbers.  At least two of them are even, and one of those is a multiple of 4, so the product is a multiple of 2*4 = 8.  At least one of them is a multiple of 3.  Exactly one of them is a multiple of 5.  Therefore, each element of S is a multiple of 8*3*5 = 120.  The smallest element of S is 1*2*3*4*5 = 120.  GCD of all elements of S cannot be greater than that.  Thus, GCD of all elements of S is 120.

 May 30, 2016
 #1
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The GCD of the set S is: 3, 4, 5 from the first row, which it shares with second row, and also with the third row. Therefore the GCD of the set is: 3 x 4 x 5 =60.

 May 29, 2016
 #2
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+10

The GCD of this set is: 1 x 2 x 3 x 4 x 5=120. Because ALL are shared by the second and third set. 2 is shared directly with the second set, but indirectly with the third set, because it is embeded in 6 of the third set, since 6=2 x 3.

 May 29, 2016
 #3
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+20
Best Answer

Each element of S is a product of 5 consequtive numbers.  At least two of them are even, and one of those is a multiple of 4, so the product is a multiple of 2*4 = 8.  At least one of them is a multiple of 3.  Exactly one of them is a multiple of 5.  Therefore, each element of S is a multiple of 8*3*5 = 120.  The smallest element of S is 1*2*3*4*5 = 120.  GCD of all elements of S cannot be greater than that.  Thus, GCD of all elements of S is 120.

Guest May 30, 2016

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