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Tracy had a bag of candies, and none of the candies could be broken into pieces. She ate 1/3 of them and then gave 1/4 of what remained to her friend Rachel. Tracy and her mom then each ate 15 candies from what Tracy had left. Finally, Tracy's brother took somewhere from one to five candies, leaving Tracy with three candies. How many candies did Tracy have at the start?

Guest Dec 2, 2018

#1**+2 **

\(\text{tracy had }n \text{ candies}\\ \text{she ate }\dfrac 1 3 \text{ of these leaving }\dfrac{2n}{3}\\ \text{she gave }\dfrac 1 4 \text{ of them to Rachel leaving }\dfrac 3 4 \dfrac{2n}{3}=\dfrac n 2\\ \text{Tracy and mom ate 30 candies from the }\dfrac{n}{2} \text{ that tracy had left}\\\text{Tracy's brother took from }1-5 \text{ candies, leaving }3 \text{ left}\)

\(\text{so condensing that down }\\ \dfrac n 2 - 30 -b = 3,~b\in 1,2,\dots 5\\ n=2(33+b)\\ \text{we note that }\dfrac n 3 \in \mathbb{N}\\ \text{so it must be that }b=3,~n=72\)

.Rom Dec 2, 2018

#1**+2 **

Best Answer

\(\text{tracy had }n \text{ candies}\\ \text{she ate }\dfrac 1 3 \text{ of these leaving }\dfrac{2n}{3}\\ \text{she gave }\dfrac 1 4 \text{ of them to Rachel leaving }\dfrac 3 4 \dfrac{2n}{3}=\dfrac n 2\\ \text{Tracy and mom ate 30 candies from the }\dfrac{n}{2} \text{ that tracy had left}\\\text{Tracy's brother took from }1-5 \text{ candies, leaving }3 \text{ left}\)

\(\text{so condensing that down }\\ \dfrac n 2 - 30 -b = 3,~b\in 1,2,\dots 5\\ n=2(33+b)\\ \text{we note that }\dfrac n 3 \in \mathbb{N}\\ \text{so it must be that }b=3,~n=72\)

Rom Dec 2, 2018