if a train is traveling north at 10 miles per hour and a second train is traveling south at 5 miles per hour at what point will the meet if they start 150 miles apart
Let the point where the one traveling 10 mph be (0,0).......let the other start at (0,150)
So
!0T + 5T = 150 where T is the total time traveled.........simplify
15T = 150 divide both sides by 15
T = 10 They meet after 10 hours.......so using the faster train's rate......
10(10) = 100...... They meet at the point (0, 100)......in other words, at the point 100 miles north of where the faster train began
Let the point where the one traveling 10 mph be (0,0).......let the other start at (0,150)
So
!0T + 5T = 150 where T is the total time traveled.........simplify
15T = 150 divide both sides by 15
T = 10 They meet after 10 hours.......so using the faster train's rate......
10(10) = 100...... They meet at the point (0, 100)......in other words, at the point 100 miles north of where the faster train began
if a train is traveling north at 10 miles per hour and a second train is traveling south at 5 miles per hour at what point will the meet if they start 150 miles apart
Since the LCM of 5 and 10=10, therefore the two train will meet after 10 hours of travel.
North-bound train will have travelled: 10 X 10=100 miles or 2/3 of the distance, and,
South-bound train will have travelled: 10 X 5 =50 miles or 1/3 of the distance.