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if a train is traveling north at 10 miles per hour and a second train is traveling south at 5 miles per hour at what point will the meet if they start 150 miles apart

 Dec 29, 2015

Best Answer 

 #1
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Let the point where the one traveling 10 mph be (0,0).......let the other start at (0,150)

 

So

 

!0T + 5T  = 150         where T is the total time traveled.........simplify

 

15T = 150                divide both sides by 15

 

T = 10                      They meet after 10 hours.......so  using the faster train's rate......

 

10(10)  = 100......      They meet at the point (0, 100)......in other words, at the point 100 miles north of where the faster train began

 

 

 

cool cool cool

 Dec 29, 2015
 #1
avatar+128473 
+5
Best Answer

Let the point where the one traveling 10 mph be (0,0).......let the other start at (0,150)

 

So

 

!0T + 5T  = 150         where T is the total time traveled.........simplify

 

15T = 150                divide both sides by 15

 

T = 10                      They meet after 10 hours.......so  using the faster train's rate......

 

10(10)  = 100......      They meet at the point (0, 100)......in other words, at the point 100 miles north of where the faster train began

 

 

 

cool cool cool

CPhill Dec 29, 2015
 #2
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+5

if a train is traveling north at 10 miles per hour and a second train is traveling south at 5 miles per hour at what point will the meet if they start 150 miles apart

 

Since the LCM of 5 and 10=10, therefore the two train will meet after 10 hours of travel.

North-bound train will have travelled: 10 X 10=100 miles or 2/3 of the distance, and,

South-bound train will have travelled: 10 X 5  =50 miles or 1/3 of the distance.

 Dec 29, 2015

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