The perimeter of a rectangle if the width is w centimeters and the length is 8cm more than twice the width.

Do not simplify.

Guest Jan 30, 2019

#1**+1 **

Perimeter = 2L + 2W

L being the length, W being the width.

So:

if the Length is 8cm more than twice the width, we have:

2W+8

so it's:

perimeter of a rectange = 2(2W+8)+2W

You asked me not to simplify it, so that should be your answer.

noobieatmath Jan 30, 2019

#1**+1 **

Best Answer

Perimeter = 2L + 2W

L being the length, W being the width.

So:

if the Length is 8cm more than twice the width, we have:

2W+8

so it's:

perimeter of a rectange = 2(2W+8)+2W

You asked me not to simplify it, so that should be your answer.

noobieatmath Jan 30, 2019

#2**-1 **

What is the perimeter of a rectangle?

It is \(2l+2w\), where \(l\) is the length and \(w\) is the width.

However, we can write \(l\) in terms of \(w\), because it says so up in the question.

\(l=2w+8\) because twice the width is \(2w\), and we add 8.

\(w=w\)

Substituting, we get \(2(2w+8)+2(w)=2(2w+8)+2w\).

According to you, we should not simplify.

You are very welcome!

:P

CoolStuffYT Jan 30, 2019