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The perimeter of a rectangle if the width is w centimeters and the length is 8cm more than twice the width.

Do not simplify.

 Jan 30, 2019

Best Answer 

 #1
avatar+144 
+1

Perimeter = 2L + 2W 

 

L being the length, W being the width.

 

So:

 

if the Length is 8cm more than twice the width, we have:

 

2W+8

 

so it's:

 

perimeter of a rectange = 2(2W+8)+2W

 

You asked me not to simplify it, so that should be your answer.

 Jan 30, 2019
 #1
avatar+144 
+1
Best Answer

Perimeter = 2L + 2W 

 

L being the length, W being the width.

 

So:

 

if the Length is 8cm more than twice the width, we have:

 

2W+8

 

so it's:

 

perimeter of a rectange = 2(2W+8)+2W

 

You asked me not to simplify it, so that should be your answer.

noobieatmath Jan 30, 2019
 #2
avatar+1108 
-1

What is the perimeter of a rectangle?

It is \(2l+2w\), where \(l\) is the length and \(w\) is the width.

However, we can write \(l\) in terms of \(w\), because it says so up in the question.

 

\(l=2w+8\) because twice the width is \(2w\), and we add 8.

\(w=w\)

 

Substituting, we get \(2(2w+8)+2(w)=2(2w+8)+2w\).

According to you, we should not simplify.

 

You are very welcome!

:P

 Jan 30, 2019

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