The perimeter of a rectangle if the width is w centimeters and the length is 8cm more than twice the width.
Do not simplify.
Perimeter = 2L + 2W
L being the length, W being the width.
So:
if the Length is 8cm more than twice the width, we have:
2W+8
so it's:
perimeter of a rectange = 2(2W+8)+2W
You asked me not to simplify it, so that should be your answer.
Perimeter = 2L + 2W
L being the length, W being the width.
So:
if the Length is 8cm more than twice the width, we have:
2W+8
so it's:
perimeter of a rectange = 2(2W+8)+2W
You asked me not to simplify it, so that should be your answer.
What is the perimeter of a rectangle?
It is \(2l+2w\), where \(l\) is the length and \(w\) is the width.
However, we can write \(l\) in terms of \(w\), because it says so up in the question.
\(l=2w+8\) because twice the width is \(2w\), and we add 8.
\(w=w\)
Substituting, we get \(2(2w+8)+2(w)=2(2w+8)+2w\).
According to you, we should not simplify.
You are very welcome!
:P