We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
77
2
avatar

The perimeter of a rectangle if the width is w centimeters and the length is 8cm more than twice the width.

Do not simplify.

 Jan 30, 2019

Best Answer 

 #1
avatar+143 
+1

Perimeter = 2L + 2W 

 

L being the length, W being the width.

 

So:

 

if the Length is 8cm more than twice the width, we have:

 

2W+8

 

so it's:

 

perimeter of a rectange = 2(2W+8)+2W

 

You asked me not to simplify it, so that should be your answer.

 Jan 30, 2019
 #1
avatar+143 
+1
Best Answer

Perimeter = 2L + 2W 

 

L being the length, W being the width.

 

So:

 

if the Length is 8cm more than twice the width, we have:

 

2W+8

 

so it's:

 

perimeter of a rectange = 2(2W+8)+2W

 

You asked me not to simplify it, so that should be your answer.

noobieatmath Jan 30, 2019
 #2
avatar+626 
-1

What is the perimeter of a rectangle?

It is \(2l+2w\), where \(l\) is the length and \(w\) is the width.

However, we can write \(l\) in terms of \(w\), because it says so up in the question.

 

\(l=2w+8\) because twice the width is \(2w\), and we add 8.

\(w=w\)

 

Substituting, we get \(2(2w+8)+2(w)=2(2w+8)+2w\).

According to you, we should not simplify.

 

You are very welcome!

:P

 Jan 30, 2019

3 Online Users