The area of an isosceles trapezoid ABCD is 24 cm2, and the diameter of an inscribed circle is 4.8 cm. Find the perimeter of the trapezoid.
The height of the trapezoid = the diameter of the circle = 4.8 cm
Call the sum of the bases , S
So
24 = (1/2) (4.8) (S)
24 = 2.4 S
24 /2.4 = S = 10
And BC = 1/2 S = 5 = AD
So.....the perimeter = S + 5 + 5 = 10 + 5 + 5 = 20 cm