Trapezoid $ABCD$ is inscribed in the semicircle with diameter $\overline{AB}$, as shown below. If $CD = 7$, $AD = 5$, and $BC = 2$, then find the radius of the semicircle.

kittykat Dec 17, 2023

#1**0 **

To solve this problem, we can follow these steps:

1. Identify relevant relationships:

Since ABCD is inscribed in the semicircle, radius r is half the diameter AB, i.e., r = AB/2.

We can use the Pythagorean theorem in triangles ADC and CBD to relate side lengths.

2. Apply the Pythagorean theorem in triangle ADC:

We know AD = 5 and CD = 7. Let AC = x. Applying the Pythagorean theorem:

x^2 + 5^2 = 7^2

x^2 = 24

x = 2sqrt(6)

3. Apply the Pythagorean theorem in triangle CBD:

We know BC = 2 and CD = 7. Let BD = y. Applying the Pythagorean theorem:

y^2 + 2^2 = 7^2

y^2 = 45

y = 3sqrt(5)

4. Find AB using side lengths from triangles:

AB = AD + BD = 5 + 3sqrt(5)

5. Calculate the radius:

r = AB/2 = (5 + 3sqrt(5))/2

Therefore, the radius of the semicircle is (5 + 3sqrt(5))/2.

BuiIderBoi Dec 17, 2023