The area of a trapezoid is $80$. The length of one base is $4$ units greater than the other base, and the height of the trapezoid is $12$. Find the perimeter of the trapezoid.
We set the smaller base to x, so the area of the trapezoid is
12x+24=80
12x=56
x=193
Next, we find the diagonals by using pythagorean theorum.
a = 2
b = 12
c = √148 = 2√39
so the perimeter is 2x+4+2c = 38/3 + 4 + 4 root 39, or 503+4√39
+1776 
