The area of the trapezoid ABCD is equal to 60. The length of one of of the bases is 9 units greater than the other base, and the height of trapezoid ABCD is equal to 8. What is the legth of the median of trapezoid ABCD
AB = x CD = x + 9
{(2x + 9) /2}*8 = 60 x = 3
Median M = 1/2(AB + CD) M = 7.5
