The area of the trapezoid ABCD is equal to 60. The length of one of of the bases is 7 units greater than the other base, and the height of trapezoid ABCD is equal to 6. What is the legth of the median of trapezoid ABCD
[ABCD] = 60
AB = x CD = x + 7 h = 6
1/2(x + x + 7)*6 = 60 x = 6.5
AB = 6.5 CD = 13.5
Median = 1/2(6.5 + 13.5)