Let WXYZ be a trapezoid with bases XY and WZ. In this trapezoid, ZXW=105 degrees, XWZ=48 degrees, and XYZ=141 degrees. Find YXZ, in degrees.
Since XY and WZ are the bases of a trapezoid, they are parallel to each other.
This makes: angle(ZWX) + angle(YXW) = 180o.
Therefore: angle(ZWX) + angle(WXZ) + angle(ZXY) = 180o.
---> 48o + 105o + angle(ZXY) = 180o
Can you take it from here?
[The size of angle(XYZ) is not important.]
Since XY and WZ are the bases of a trapezoid, they are parallel to each other.
This makes: angle(ZWX) + angle(YXW) = 180o.
Therefore: angle(ZWX) + angle(WXZ) + angle(ZXY) = 180o.
---> 48o + 105o + angle(ZXY) = 180o
Can you take it from here?
[The size of angle(XYZ) is not important.]