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# trapezoid

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Let WXYZ be a trapezoid with bases XY and WZ. In this trapezoid, ZXW=105 degrees, XWZ=48 degrees, and XYZ=141 degrees. Find YXZ, in degrees.

Mar 8, 2022

#1
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Since XY and WZ are the bases of a trapezoid, they are parallel to each other.

This makes:  angle(ZWX) + angle(YXW)  =  180o.

Therefore:  angle(ZWX) + angle(WXZ) + angle(ZXY)  =  180o.

--->                 48o        +       105o      + angle(ZXY)  =  180o

Can you take it from here?

[The size of angle(XYZ) is not important.]

Mar 8, 2022

#1
+1

Since XY and WZ are the bases of a trapezoid, they are parallel to each other.

This makes:  angle(ZWX) + angle(YXW)  =  180o.

Therefore:  angle(ZWX) + angle(WXZ) + angle(ZXY)  =  180o.

--->                 48o        +       105o      + angle(ZXY)  =  180o

Can you take it from here?

[The size of angle(XYZ) is not important.]

geno3141 Mar 8, 2022
#2
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ZXW=105 degrees       and      XYZ=141 degrees.   <======not sure this is possible but I geno's method will get you the answer

Mar 8, 2022
#3
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Never mind...... my mistake here.

Guest Mar 8, 2022