Given an isosceles trapezoid with bases of 8 and 18 and an area of 120 square units, what is the number of units in the length of one of the non-parallel sides?
Given an isosceles trapezoid with bases of 8 and 18 and an area of 120 square units, what is the number of units in the length of one of the non-parallel sides?
Area of a trapezoid is the height times half the sum of the top base plus the bottom base.
A = (h) • (btop + bbottom) / 2
120 = (h) • 26 / 2
from this we get h = 120 / 13 = 9.2308
The height dropped from the top left corner intersects the bottom base at 5 from the left.
The non-parallel side of the trapezoid is the hypotenuse of the right triangle thus formed.
Use Pythagoras Theorem c2 = (9.2308)2 + (5)2 = 110.207
side = sqrt(110.207) = 10.5
When I was doing this on the calculator, I didn't round the numbers.
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