Triangle ABC has a right angle at B. Legs AB and CB are extended past point B to points D and E, respectively, such that angle EAC = angle ACD = 90. Prove that EB * BD = AB * BC.
Prove EB * BD = AB * BC
ΔEBA ~ ΔABC
ΔABC ~ ΔCBD
So.....
ΔEBA ~ ΔCBD
EB/BA = CB/BD
EB/AB = BC/BD
So......
EB * BD = AB * BC