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Triangle ABC has a right angle at B. Legs AB and CB are extended past point B to points D and E, respectively, such that angle EAC = angle ACD = 90. Prove that EB * BD = AB * BC.

 Dec 8, 2016
 #1
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Prove  EB * BD = AB * BC   

 

ΔEBA  ~  ΔABC

 

ΔABC  ~  ΔCBD

 

So.....

 

ΔEBA  ~  ΔCBD

 

EB/BA  = CB/BD

 

EB/AB  = BC/BD

 

So......

 

EB * BD =  AB * BC

 

 

 

cool cool cool

 Dec 9, 2016

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