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Parts b, c, and d are the ones I need help with most. 

 Apr 25, 2020
 #1
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To find a revolution of 270o, I would do this:  the y-value of the initial point becomes the x-value after rotation

                                                                       the negative of the initial x-value becomes teh y-value after rotation.

A(3, -2)   --->   A'(-2, -3)

B(8, 2)   --->   B'(2, -8)

C(5, 10)   --->   C'(10, -5)

 

But, graph these to check to see if this works!

 

I'm assuming that the notation "T1,-6" means a translation of 1 of the x-value and -6 of the y-value:

A(3, -2)   --->   A''(4, -8)

B(8, 2)   --->   B''(9, -4)

C(5, 10)   --->   C''(6, 4)

 

To see whether they are congruent or not, graph them and measure. My initial response is that they will be congruent because rotations and translation preserve distance and angles.

 Apr 25, 2020

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