Triangle ABC is an oblique triangle. If angle A equals 57°, angle B equals 73°, and AB equals 24 in, what is the length of AC?
The AC has a line on top to by the way. please help thanks! :)
Angle C must = [180 - 73 - 57 ] = [180 - 130] = 50°
And using rhw Law if Sines, we have.....
AB/sin C = AC/sin B → 24/sin(50) = AC/sin(73) → AC = 24*sin(73)/sin(50) = about 29.96 in