Triangle ABC is given and angle B = 38 degrees Angle C is the right angle CA is X and CB is 4.5 I have no clue how to find x ?

We can use trig to solve this....we have

tan(38) = x / 4.5      multiply both sides by 4.5

(4.5)tan(38) =  x =  about 3.5

You need either the AB or AC's length's. Then you can use the formula A²+B²=H² (if you get the AC length) or H²-A²=B² (if you get the AC length).

Triangle ABC is given and angle B = 38 degrees Angle C is the right angle CA is X and CB is 4.5 I have no clue how to find x ?

B = 38^o,      CB = 4.5,     CA = X

tan(B) = X/CB

tan38^o = X/4.5

X = tan38^o * 4.5

X = 3.52