Find the area of an isosceles triangle with two sides being 1 and an angle A being 30.
Guest, you have not specified the exact location of the measure of the 30-degree angle. There are 2 possibilities.
There are two possibilities.....
If the apex angle between the two equal sides is 30°, the area is
(1/2)* 1^2 * sin (30) =
(1/2) (1/2) =
1/4 units^2
If the equal angles opposite the equal sides = 30°, the apex angle = 120° and the area is
(1/2)* 1^2 * sin (120) =
(1/2)(√3/2) =
√3/4 units^2