Triangle BAC is 95 degree, with BA 6.8CM and BC 8.1. Find angle BCA

Triangle BAC is 95 degree, with BA 6.8CM and BC 8.1. Find angle BCA

We have a SSA situation here, so there's a possibility of more than one triangle

We have

sin95/ 8.1 = sin BCA / 6.8

And, using the sine inverse, we have

sin-1 (6.8 * sin95 / 8.1) = about 56.75°

So....angle ABC = (180 - 95- 56.75) = 28.25°

Now, ABC might also be supplementary to 28.25° = 151.75°

But, since BAC is 95°, this is impossible, because BAC + ABC would be greater than 180°

So....only one triangle exists.....