A triangle with vertices $A,B,C$ with coordinates $\left(2,\frac{1}{2}\right)$, $\left(4,\frac{1}{4}\right)$, $\left(3,\frac{1}{3}\right)$ has orthocentre at $H$. Find the coordinates of $H$.
We're going to find the average of everything. (2+4+3)/3 = 3 (1/2 + 1/4 + 1/3)/3 = 13/36.
So our center is (3, 13/36)
I hope this helped. :)))
=^._.^=
The orthocenter for that triangle is somewhere in the third quadrant.
corrections: of instead of for
