In right triangle ABC, CAB is a right angle. Point M is the midpoint of BC. What is the number of centimeters in the length of median AM? Express your answer as a decimal to the nearest tenth.
To find the median of a triangle, you use the formula $MA=\dfrac12\sqrt{2CA^2+2BA^2-CB^2}=\dfrac12\sqrt{50+288-169}=\dfrac12\cdot13=\boxed{\dfrac{13}2}$
To find the median of a triangle, you use the formula $MA=\dfrac12\sqrt{2CA^2+2BA^2-CB^2}=\dfrac12\sqrt{50+288-169}=\dfrac12\cdot13=\boxed{\dfrac{13}2}$