The hyponetuse (m) and one leg (n) of a right triangle differ by 2. The square of the other side is
a) m+2n
b) m+n
c) 2(m-n)
d) 2(m+n)
e) m-2n
+130081 None of these
We know that m - 2 = n ⇒ m = n + 2
So....using the Pythagorean Theorem....we have that the remaining side =
√ [ m^2 - n^2 ]
√ [ ( n + 2)^2 - n^2 ] simplify
√ ( n^2 + 4n + 4 - n^2 )
√ [4n + 4]
So....the square of this side = 4n + 4 [ in terms of n ]
