In the triangle above, please find AC.
Angle C = 180 - 15 - 45 = 120
Using the Law of Sines
AC / sin B = AB /sin C
AC / sin45 = 2sqrt 3 / sin 120
AC = 2sqrt 3 * sin 45 / sqrt (3) / 2
AC = 2sqrt (3) (sqrt (2) / 2 ) * 2 /sqrt (3)
AC = 2sqrt (2)
