Find the inradius of triangle ABC.
Find the circumradius of triangle ABC.
We have a 6-8-10 right triangle
The circumradius = (1/2) hypotenuse = 5
The inradius = ( height + base - sqrt ( height^2 + base^2) ) / 2 =
( 6 + 8 - sqrt ( 6^2 + 8^2) ) / 2 =
(14 - sqrt (100) ) / 2 =
(14 -10 ) / 2 =
4/2 =
2
