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As shown in the diagram $\angle BAC=90^\circ$.  Let $X$ be the foot of the altitude from $A$ to $\overline {BC}$, $\overline{AY}$ be the bisector of $\angle BAC$, and $\overline{AZ}$ be the median of $\triangle ABC$. If $\angle XAY = 16^\circ$, then what is the measure of $\angle AYB$ in degrees?

 Jan 9, 2024
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avatar+128732 
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Changing angle XAY to  16°

Then angle  AYX  = angle  AYB =  measure (AXY) - measure (XAY ) =    90°  - 16°  =  74°

 

 

cool cool cool

 Jan 9, 2024
edited by CPhill  Jan 9, 2024

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