In triangle $ABC,$ the angle bisector of $\angle BAC$ meets $\overline{BC}$ at $D.$ If $\angle BAC = 60^\circ,$ $\angle CAD = 45^\circ,$ and $AD = 24,$ then find the area of triangle $ABC.$
A 60
24
B D C
If BAC is 60° and AD is a bisector of BAC, then angle CAD must = 30°, not 45°
+1415 
