The lengths of two sides of a triangle are 33 units and 42 units. The third side also has an integral length. What is the greatest possible number of units in the perimeter of the triangle?
Using the triangle inequality
33 + 42 > than the remaining side length
75 > than the remaining side length
So.......the max length for the remaining side = 74
And the max perimeter = 33 + 42 + 74 = 149
