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Suppose that there is a right triangle $\triangle ABC$ such that the legs $AB$ and $BC$ have lengths $4\sqrt{2}$ and $5,$ respectively. What is the length of the median $BM$?

 Jan 13, 2024
 #1
avatar+128448 
+1

4sqrt 2 =  sqrt 32

 

Length of  hypotenuse =  sqrt [ (sqrt 32)^2  + 5^2 ] =  sqrt [ 57 ] 

 

BM is a  median drawn  to  the  hypotenuse...its length = 1/2 *hypotenuse length =  sqrt (57) / 2 ≈ 3.77 

 

cool cool cool

 Jan 13, 2024

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