Suppose that there is a right triangle $\triangle ABC$ such that the legs $AB$ and $BC$ have lengths $4\sqrt{2}$ and $5,$ respectively. What is the length of the median $BM$?
4sqrt 2 = sqrt 32
Length of hypotenuse = sqrt [ (sqrt 32)^2 + 5^2 ] = sqrt [ 57 ]
BM is a median drawn to the hypotenuse...its length = 1/2 *hypotenuse length = sqrt (57) / 2 ≈ 3.77
+1439 
