Find the circumradius of triangle $ABC.$
Area:
\(= \sqrt {\frac {3a} {2} \left( \frac {3a} {2} - a \right)^3} = \sqrt {\frac {3a^4} {2^4}} = \frac {a^2} {4} \sqrt {3}\)
Circumradius:
\(= \frac {a^3} {\frac {a^2} {4} \sqrt {3}} = \frac {4a} {\sqrt {3}} = \frac {4\sqrt{3} a} {3}\)