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Find the circumradius of triangle $ABC.$

 

 Mar 25, 2024
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Area:

\(= \sqrt {\frac {3a} {2} \left( \frac {3a} {2} - a \right)^3} = \sqrt {\frac {3a^4} {2^4}} = \frac {a^2} {4} \sqrt {3}\)

Circumradius:

\(= \frac {a^3} {\frac {a^2} {4} \sqrt {3}} = \frac {4a} {\sqrt {3}} = \frac {4\sqrt{3} a} {3}\)

 Mar 25, 2024

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