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# Triangle

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In triangle JKL, we have JK = JL = 25 and KL = $$20$$. Find the circumradius.

Apr 17, 2022

#1
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We calculate the area of the triangle.

Area of triangle JKL = $$\dfrac12 \cdot 20 \cdot \sqrt{25^2 - \left(\dfrac{20}2\right)^2} = 50\sqrt{21}$$

Then, we use the formula $$\text{circumradius} = \dfrac{\text{product of 3 sides}}{4(\text{area})}$$.

$$\text{circumradius} = \dfrac{25(25)(20)}{4(50\sqrt{21})} = \dfrac{125}{42}\sqrt{21}$$

Wolfram Alpha Output

My answer to a similar problem

Apr 17, 2022

#1
+9369
+1

We calculate the area of the triangle.

Area of triangle JKL = $$\dfrac12 \cdot 20 \cdot \sqrt{25^2 - \left(\dfrac{20}2\right)^2} = 50\sqrt{21}$$

Then, we use the formula $$\text{circumradius} = \dfrac{\text{product of 3 sides}}{4(\text{area})}$$.

$$\text{circumradius} = \dfrac{25(25)(20)}{4(50\sqrt{21})} = \dfrac{125}{42}\sqrt{21}$$

Wolfram Alpha Output

My answer to a similar problem

MaxWong Apr 17, 2022