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In triangle $ABC,$ $\angle C = 90^\circ.$ A semicircle is constructed along side $\overline{AC}$ that is tangent to $\overline{BC}$ and $\overline{AB}.$ If the radius of the semicircle is equal to $\frac{BC}{3},$ then find $\frac{AC}{BC}.$

 Mar 2, 2024
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Here :  https://web2.0calc.com/questions/pls-help_13322

 

 

cool cool cool

 Mar 3, 2024

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