The sides of a triangle are $2,$ $2,$ and $\sqrt{6} - \sqrt{3}.$ Enter the angles of the triangle in degrees, separated by commas.
The triangle is isosceles....let the base = (sqrt 6 - sqrt (3)
cos ( base angle) = ( [ sqrt 6 -sqrt 3 ] / 2 ) / 2 = [sqrt 6 - sqrt 3 ] / 4
arccos ( [ sqrt 6 -sqrt 3 ] / 4 ) ≈ 79.7°
Apex angle = 180 - 2(79.7) ≈ 20.6°
Angles are 20.6° , 79.7° , 79.7°
+1752 
