In triangle ABC, point X is on side BC such that AX=13,BX=10,CX=10, and the circumcircles of triangles ABX and ACX have the same radius. Find the area of triangle ABC.
Find the area of triangle ABC.
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\(\overline{AC}=\overline{AB}\)
\(\Delta\ ACX\ \equiv \Delta\ ABX\)
\(A_{ABC}=\frac{(\overline{AX}+\overline{CX})\cdot \overline{AX}}{2}=\frac{(10+10)\cdot 13}{2}\\ \color{blue}A_{ABC}=130\)
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