+0  
 
+3
68
3
avatar+108 

A right triangle has legs of length 6 and x, and a hypotenuse of length y. The perimeter of the triangle is 18. Compute y.

 Feb 28, 2020
 #1
avatar+109450 
+1

We  have  that

 

6 +  x  +  y    =  18

 

And  we  know  that   y  = sqrt  [ 6^2  + x^2]

 

So  we  have  that

 

6 + x  + sqrt [ 6^2  + x^2]   =  18     simplify

 

x + sqrt [ 6^2  + x^2 ] =  12

 

sqrt [ 6^2  + x^2]  =  12  - x         square  both sides

 

6^2 + x^2  =  x^2  - 24x  + 144        rearrange  as

 

24x - 144 + 6^2  =  0

 

24x  - 144 + 36  =  0

 

24x  -  108   =  0

 

24x  =  108

 

x =  108/24   =   9/2   = 4.5

 

So

 

y =  sqrt [6^2  + 4.5^2 ]  =  sqrt  [ 36  + 20,25 ]  =   sqrt  [56.25 ] =   7.5

 

CORRECTED ANSWER!!!

 

 

cool cool cool

 Feb 28, 2020
edited by CPhill  Feb 28, 2020
 #2
avatar+108 
+4

That's wrong it says

 Feb 28, 2020
 #3
avatar+109450 
+1

Sorry, brian......

 

See my corrected  answer   !!!

 

cool cool cool

CPhill  Feb 28, 2020

24 Online Users

avatar