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A standard baseball diamond is a square 90 feet on each side. Find the distance of a throw made from the catcher 3 feet behind home plate in an attempt to throw out a runner trying to steal second base. Round to the nearest whole number.

 

What I mainly don't understand in this problem is how this situation would look. I also am not sure what a throw out is. Could anybody simply provide me with a visual of this problem?

 

Thanks!

 Jan 25, 2021

4+0 Answers

 #1
avatar+128407 
+1

The diagonal of  the  square  will  be  the  distance  from  home plate to  second base

 

The diagonal of a square =  side * sqrt (2)

 

So....This distance  is    90 * sqrt (2)  ≈  127.28 ft  = 127 ft

 

So .....from 3  ft behind home plate  the distance =    127 +  3  =   130 ft

 

 

cool cool cool

 Jan 25, 2021
 #2
avatar+88 
0

So would the length that the catcher throws be the diagonal of the diamond + 3?

grs75  Jan 25, 2021
 #3
avatar+128407 
0

Correct.....

 

cool cool cool

CPhill  Jan 25, 2021
 #4
avatar+88 
0

Oh okay! Thank you!

grs75  Jan 25, 2021

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