A standard baseball diamond is a square 90 feet on each side. Find the distance of a throw made from the catcher 3 feet behind home plate in an attempt to throw out a runner trying to steal second base. Round to the nearest whole number.
What I mainly don't understand in this problem is how this situation would look. I also am not sure what a throw out is. Could anybody simply provide me with a visual of this problem?
The diagonal of the square will be the distance from home plate to second base
The diagonal of a square = side * sqrt (2)
So....This distance is 90 * sqrt (2) ≈ 127.28 ft = 127 ft
So .....from 3 ft behind home plate the distance = 127 + 3 = 130 ft