triangles

I have a triangle with C = 90 degrees and a c = 166 cm and last but not least an a = 130,96 cm 

which formulas and calculations do i have to do to find out the missing lengths (A,b, B) ?

$$\\\small{\text{$ \begin{array}{rcl} \sin{(A)}&=&\dfrac{a}{c}\\\\ \sin{(A)}&=&\dfrac{ 130.96~\rm{cm} }{ 166.00~\rm{cm} }\\\\ \sin{(A)}&=&0.78891566265\\\\ A&=&52.0842936445\ensurement{^{\circ}} \end{array} $}}\\\\\\ \small{\text{$ \begin{array}{rcl} B&=& 90\ensurement{^{\circ}} - A\\\\ B&=& 90\ensurement{^{\circ}} - 52.0842936445\ensurement{^{\circ}}\\\\ B&=& 37.9157063555\ensurement{^{\circ}}\\\\ \end{array} $}}\\\\ \\\small{\text{$ \begin{array}{rcl} \sin{(B)}&=&\dfrac{b}{c}\\\\ b &=& c\cdot \sin{(B)}\\\\ b &=& 166.00~\rm{cm} \cdot \sin{(37.9157063555\ensurement{^{\circ}})}\\\\ b &=& 166.00~\rm{cm} \cdot 0.61450148676 \\\\ b &=& 102.01~\rm{cm} \\\\ \end{array} $}}$$

Thank you very much. I did get 0,7889... but i forgot to calculate with sinus 

Big thanks from dk, heureka :)