In right triangle ABC with \(\angle A = 90^\circ\), we have AB = 6 and BC = 10. Find \(\cos A\).
Answer with an exact number.
Since AB = 6 and BC = 10, AC = 8 (Pythagorean Theorem)
cos(A) = 8 / 10.
Im really bad at trig
don trust me but
We have Pythagorean theorem, 36+x=100, x=64, AC=8.
Now, cos A would then be i THINK AC/BC, which is 8/10. Or, exactly 0.800000000.