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In right triangle ABC with \(\angle A = 90^\circ\), we have AB = 6 and BC = 10. Find \(\cos A\).

Answer with an exact number.

 Aug 6, 2020
 #1
avatar+21953 
+1

Since  AB = 6  and  BC = 10,  AC  = 8    (Pythagorean Theorem)

 

cos(A)  =  8 / 10.

 Aug 6, 2020
 #2
avatar+169 
+1

Im really bad at trig

don trust me but

We have Pythagorean theorem, 36+x=100, x=64, AC=8.

Now, cos A would then be i THINK AC/BC, which is 8/10. Or, exactly 0.800000000.

 Aug 6, 2020

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