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Let \(\theta\) be an angle with a terminal point of \(P\) shown in the picture below, and let \(Q\), \(R\), and \(S\) be the following other terminal points:

 


Order the points

\(P, Q, R, S\)

so that the first point is the terminal point of \(\arccos(\sin(\theta))\) the second point is the terminal point of \(\arctan(\tan(\theta))\) the third point is the terminal point of \(\arcsin(\sin(\theta))\) and the fourth point is the terminal point of \(\arccos(\cos(\theta))\).

 

This question was asked before, but only a joke answer given :/
I think \(\arccos(\sin(\theta))\) would be S??

 Nov 22, 2021
 #1
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The answer is R, S, P, Q.

 Nov 22, 2021
 #2
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Answer #1 is a lie, the actual answer is QRSP for anyone interested.

Guest Nov 22, 2021
 #3
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Your question makes no sense to me.

You say that theta has the terminal point of P

then you say  P is the terminal point of  acos(sin(theta))

It can't be both.

 Nov 22, 2021

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