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sec² π/6 + 3cot π/6

 May 26, 2016
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sec² π/6 + 3cot π/6

 

 

pi/6 radians = 30 degrees

 

\(sec² 30 + 3cot30\\= (1 \div cos^230)+3(1\div tan30)\\ = (\frac{2}{\sqrt3})^2+3(\sqrt3)^2\\ = \frac{4}{3}+3*3\\ = \frac{4}{3}+9\\ =10\frac{1}{3}\)

 May 26, 2016

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