what is sin(t) if cot(t)=9
cot = x/y sin = y/r r = sqrt ( x^2 + y^2) ......so we have.....
cot(t) = 9/1 r = sqrt[ 9^2 + 1^1] = sqrt [ 82]
So.....sin(t) = 1/ sqrt(82) = sqrt(82) / 82
Use right-angled triangle where
length of side opposite angle (t) = 1
length of side adjacent to angle (t)= 9
then hypotenuse length = sqrt(82)
so sin(t) =1/sqrt(82)
