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1. 2 sin 2t − 3tan 2t = 0

2.(6 cot t)2 = 108

3. 16 tan t − 16 = 0

 Apr 7, 2016
 #1
avatar+130511 
0

1. 2 sin 2t − 3tan 2t = 0

 

2sin2t - 3sin2t / cos2t = 0

 

sin2t [ 2 - 3/cos2t]  = 0

 

Set each factor to 0

 

sin2t = 0    and this occurs at  n* pi/2     where n is an integer

 

 

For the second factor, we have

 

2 - 3/cos2t  = 0

2 - 3sec(2t)  = 0    

sec(2t)  = 2/3       and there is no solution to this 

 

Here's a graph [in degrees ]  .......https://www.desmos.com/calculator/x7dws0dxus

 

 

 

cool cool cool

 Apr 8, 2016
 #2
avatar+130511 
0

I assume that the second one is :

 

[6 cot t]^2  = 108

 

36cot^2 t  =  108       divide both sides by 36

 

cot^2 t  = 3       take the square root of both sides

 

cot t  =  ± sqrt (3)

 

For the first soluton, we have

 

cot t = sqrt(3)       this occurs at   pi/6 + n*pi    where n is an integer

 

For the second solution, we have

 

cot t = - sqrt(3)       this occurs at 5pi/6 + n*pi   where n is an integer 

 

Here's the graph [in degrees] :  https://www.desmos.com/calculator/hbl4cuxc3a

 

 

cool cool cool

 Apr 8, 2016
 #3
avatar+130511 
0

3. 16 tan t − 16 = 0    divide both sides by 16

 

tant - 1  = 0

 

tan t = 1       and this occurs at  pi/4  + npi     where  n is an integer

 

 

cool cool cool

 Apr 8, 2016

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