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Simplify. cos 2 α – 1/cos α + 1

 Apr 3, 2015

Best Answer 

 #3
avatar+118724 
+5

Geno, I think your answer is as far as it goes         

but I suspect that the intended question was a different one.

there probably should be brackets somewhere.   

 Apr 4, 2015
 #1
avatar+23254 
+5

cos(2a) - 1/cos(a) + 1

cos2(a) - sin2(a) - 1/cos(a) + 1                        ( Use the identity:  cos(2a) = cos2(a) - sin2(a) )

[cos3(a) - cos(a)sin2(a) - 1 + cos(a)]/cos(a)       ( Write with the common denominator:  cos(a) )

[cos3(a) + cos(a) - cos(a)sin2(a) - 1]/cos(a)       ( Rearrange the terms )

[cos3(a) + cos(a)[1 - sin2(a)] - 1]/cos(a)            ( Factor out cos(a) )

[cos3(a) + cos(a)[cos2(a)] - 1]/cos(a)                ( Use the identity:  cos2(a) = 1 - sin2(a) )

[cos3(a) + cos3(a) - 1]/cos(a)                           ( Multiply)

[2cos3(a) - 1]/cos(a)                                                       

... and now I'm stuck! ...

 Apr 3, 2015
 #2
avatar
0

the perfect answer is

cos(2a-1)-cos(a+1)=0

 Apr 4, 2015
 #3
avatar+118724 
+5
Best Answer

Geno, I think your answer is as far as it goes         

but I suspect that the intended question was a different one.

there probably should be brackets somewhere.   

Melody Apr 4, 2015

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