Algebraically determine the exact value of sec(11pi/6+cot(8pi/3)/sin(-150). Simplify your expression completely.
picture of question: https://drive.google.com/file/d/1YFfwpDTdV7L-E4UIGbjwvDxRDAwTUG7z/view?usp=sharing
LaTex added by Melody
\(\frac{sec\frac{11\pi}{6}+cot\frac{8\pi}{3}}{sin(-150^\circ)}\)
It is very strange to have half the question in radians and half in degrees...
\(\frac{sec\frac{11\pi}{6}+cot\frac{8\pi}{3}}{sin(-150^\circ)}\\ \frac{sec\frac{-\pi}{6}+cot\frac{2\pi}{3}}{sin(360-150^\circ)}\\ \)
I really should not be doing this.
I think you either understand none of it in which case my answer will not help.
OR you are being lazy and I am just doing your homework for you.
Show us what you have done for yourself. And what exactly is troubling you.