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# trig is bad for my health :( HELP PLZ

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"Sketch the piecewise-defined function. Then determine whether the function is continuous." I'm sorry I'm new and don't know how to make the picture small, I just really really really need help  Dec 16, 2020

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You need help on  both or  just the second one ????   Dec 16, 2020
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both plz if possible

sixside  Dec 16, 2020
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First one

a)  Limit  as  x approaches infinity   = 4

b) Limit as  x approaches 3 from the left    =  7

c) Limit as x approaches  3 from the right   =  infinity  (does not exist)

d ) Limit as x approaches -1 from both sides  ≈  -3.5

e) h(-1)    = 2   Dec 16, 2020
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3) Easiest  way to do this is to evaluate  the functions as  if they WERE continuous

So

sqrt (2x  -6)    when x  =3      =  0

-(x - 1)^2  + 1  when  x  = 3    =   -3

The  first two functions are  not  continuous when  x  =  3

And

-(x - 1)^2 + 1  when x  = -1 =  -3

-2x -3  when x = -1 =  - 1

So these two functions are  not  continuous at  x  = -1

See the graph here  :  https://www.desmos.com/calculator/n8zrrd4nbn   Dec 16, 2020