+0  
 
0
101
4
avatar+18 

"Sketch the piecewise-defined function. Then determine whether the function is continuous." I'm sorry I'm new and don't know how to make the picture small, I just really really really need help

 Dec 16, 2020
 #1
avatar+117546 
+1

You need help on  both or  just the second one ????

 

cool cool cool

 Dec 16, 2020
 #2
avatar+18 
0

both plz if possible

sixside  Dec 16, 2020
 #3
avatar+117546 
+2

First one

 

a)  Limit  as  x approaches infinity   = 4

 

b) Limit as  x approaches 3 from the left    =  7

 

c) Limit as x approaches  3 from the right   =  infinity  (does not exist)

 

d ) Limit as x approaches -1 from both sides  ≈  -3.5

 

e) h(-1)    = 2

 

 

cool cool cool

 Dec 16, 2020
 #4
avatar+117546 
+2

3) Easiest  way to do this is to evaluate  the functions as  if they WERE continuous

 

So

 

sqrt (2x  -6)    when x  =3      =  0

 

-(x - 1)^2  + 1  when  x  = 3    =   -3      

 

The  first two functions are  not  continuous when  x  =  3

 

And

 

-(x - 1)^2 + 1  when x  = -1 =  -3

 

-2x -3  when x = -1 =  - 1

 

So these two functions are  not  continuous at  x  = -1

 

See the graph here  :  https://www.desmos.com/calculator/n8zrrd4nbn

 

cool cool cool

 Dec 16, 2020

63 Online Users

avatar
avatar
avatar
avatar