+18 "Sketch the piecewise-defined function. Then determine whether the function is continuous." I'm sorry I'm new and don't know how to make the picture small, I just really really really need help
+128474 First one
a) Limit as x approaches infinity = 4
b) Limit as x approaches 3 from the left = 7
c) Limit as x approaches 3 from the right = infinity (does not exist)
d ) Limit as x approaches -1 from both sides ≈ -3.5
e) h(-1) = 2
+128474 3) Easiest way to do this is to evaluate the functions as if they WERE continuous
So
sqrt (2x -6) when x =3 = 0
-(x - 1)^2 + 1 when x = 3 = -3
The first two functions are not continuous when x = 3
And
-(x - 1)^2 + 1 when x = -1 = -3
-2x -3 when x = -1 = - 1
So these two functions are not continuous at x = -1
See the graph here : https://www.desmos.com/calculator/n8zrrd4nbn
