+0  
 
+1
33
1
avatar+14 

If sec (theta)= -3 and tan (theta) > zero, what's the value of sin (theta)

 Dec 31, 2018
 #1
avatar+94209 
+2

Because the tangent is > 0   and the secant is < 0 , theta lies in the 3rd quadrant

 

The secant is -3/1  = 3 /-1  =  r /x

 

The sine will be negative here  and is given by :

 

- √ [ r^2 - x^2 ] /  r   =   - √ [ (3)^2 - (-1)^2 ] /   =   -  (√8 )  / 3

 

 

cool cool cool

 Dec 31, 2018
edited by CPhill  Dec 31, 2018

11 Online Users

avatar
avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.