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If sec (theta)= -3 and tan (theta) > zero, what's the value of sin (theta)

 Dec 31, 2018
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Because the tangent is > 0   and the secant is < 0 , theta lies in the 3rd quadrant

 

The secant is -3/1  = 3 /-1  =  r /x

 

The sine will be negative here  and is given by :

 

- √ [ r^2 - x^2 ] /  r   =   - √ [ (3)^2 - (-1)^2 ] /   =   -  (√8 )  / 3

 

 

cool cool cool

 Dec 31, 2018
edited by CPhill  Dec 31, 2018

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