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In right triangle \(ABC\) with \(\angle B = 90^\circ\), we have \(\sin A = 2 \cos A\). What is \(\cos A\)?

 

 

Please help!!!!!!!!

 Feb 5, 2021
 #1
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Hello!

 

sin(a)^2+cosine(a)^2 = 1

(2cosine(a))^2+cosine(a)^2 = 1

I'm sure you can solve it from here. 

Good luck. :)))

 

=^._.^=

 Feb 5, 2021

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