In right triangle \(ABC\) with \(\angle B = 90^\circ\), we have \(\sin A = 2 \cos A\). What is \(\cos A\)?
Please help!!!!!!!!
Hello!
sin(a)^2+cosine(a)^2 = 1
(2cosine(a))^2+cosine(a)^2 = 1
I'm sure you can solve it from here.
Good luck. :)))
=^._.^=
+180 
