Given a) state the other five trigonometric ratios as fractions.b) determine the value of θ to the nearest degree.
We are in Quad 4
r = sqrt [ 9^2 + 4^2 ] = sqrt 97
a) sin = -9/sqrt 97
cos = 4/sqrt 97
cot = -4/9
sec = sqrt (97) / 4
csc = -sqrt (97) /4
b) arctan (-9/4) = -66.04°
So....the angle is 360 - 66.04 = 293.96°
csc θ = 1/sin
So it would be θ = -√97/9, not θ = -√97/4
+180 
